IMAGE UCS2-Science-Order01.jpg

Our resultant co-Action vectors are plotted three uniquely different ways depending on
whether they are synergic or net positive (increasing order), neutral or no change
(static order), or adversary or net negative (decreasing order). Here the defined
directions of the X and Y axes, take on significance.

Synergic Co-Actions

If the co-Action vector is synergicor net positive (inreasing order), it is longer than
the radius of the zero-zero circle.

Thus it is plotted from the (0, 0) ORIGIN towards the(+, +) quadrant. A net
synergic co-Action vector
is shown in the diagram below in green ink.

IMAGE UCS2-Science-Order94.jpg

Y
(-,+)(0, +)syntropy

X

(+,+)

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

(0,0)

Axis of Atropy

entropy

The ORIGIN is fixed at 0,0. The position of the arrowhead depicts X and Y’s condition
as a result of the relationship. The arrowhead is in the (+, +) quadrant so both are
winning. Their orderin increasing. The position is equally distant from both the X
and Yaxis so they are winning equally.

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IMAGE UCS2-Science-Order01.jpg

In this example, the relationship is synergic, both X and Y are in better condition than
when they began the relationship. They have both won. They have both gained. And,
they have benefited equally from the relationship. The individual orderof both X and
Y has increased because of their interaction.

In a net positive co-Action or synergic relationship, Haskell chose the convention of
shifting the reference perimeter away from the origin. The perimeter of the reference
zero-zero circlecan only shift in the defined directions of the X and Y axes. Thus all
net positive co-Actions will lie outside the zero-zero circle.

Below, I have plotted a seven examples of netsynergic co-Actions. The sum of their
order togetheris greater than the sum of their orderindividually.

We can see that although they are all net synergicsometimes X wins more than Y
and sometimes X loses. We also see that sometimes Y wins more than X and sometimes
Y loses.

IMAGE UCS2-Science-Order96.jpg

Y
(-,+)(0, +)syntropy

X

(+,+)

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

Axis of Atropy

entropy

(0,0)

In a net synergic co-Action the area of the circle shifts to the right and above the
reference zero-zero circle.

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IMAGE UCS2-Science-Order01.jpg
IMAGE UCS2-Science-Order98.jpg

Y
(-,+)(0, +)syntropy

X

(+,+)

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

Axis of Atropy

entropy

(0,0)

Above, we also see the synergic gain— the cooperator's surplus ( +Z) outside the
zero-zero circle to the right and above the Axis of Atropy.

Y

IMAGE UCS2-Science-Order99.jpg

X

(+,+)

(-,+)(0, +)syntropy

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

Axis of Atropy

entropy

(0,0)

+Z

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IMAGE UCS2-Science-Order01.jpg

Below, I have removed the net synergic co-Action vectors.

IMAGE UCS2-Science-Order101.jpg

Y
(-,+)(0, +)syntropy

X

(+,+)

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

Axis of Atropy

entropy

(0,0)

+Z

Now ,we can more easily see the synergic gain filled in withgreen ink. This is what
Haskellcalled the cooperator's surplus( +Z).

It falls outside the zero-zero circle to the right and above the Axis of Atropy. This
represents the net increase in orderfound in a synergic relationship.

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IMAGE UCS2-Science-Order01.jpg

Neutral Co-Actions

If the co-Action vector is net neutralor no change (static order), it is equal to the
radius of the zero-zero circle. A net neutralco-Action is plotted on the Axis of
Atropy shown below in light blue ink.

IMAGE UCS2-Science-Order103.jpg

Y
(-,+)(0, +)syntropy

X

(+,+)

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

(0,0)

Axis of Atropy

entropy

The center of the net neutral Co-Actionis hi-lighted in dark blueto better
designate the reality of Y’s winning at the expense of X’s losing. The position of the
dark blue dotshows that X's position is shifted to the right of the Y Axis and that Y's
position is shifted above the X axis.

Below, I have plotted a net neutral co-Actionin which X and Y have simply drawn
(as in win, loseor draw).neither of them are winning or losing. Their relationship
has had no effect on each others condition. Their orderhas remained the same.

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IMAGE UCS2-Science-Order01.jpg
IMAGE UCS2-Science-Order105.jpg

Y
(-,+)(0, +)syntropy

X

(+,+)

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

(0,0)

Axis of Atropy

entropy

Next, I have plotted seven net neutral co-Actions. The co-Action vectorsoverlap, but
we can distinguish them by their centers.

Y

IMAGE UCS2-Science-Order106.jpg

X

(+,+)

(-,+)(0, +)syntropy

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

(0,0)

Axis of Atropy

entropy

We see that although they are all net neutralsometimes X wins to Y’s loss and

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IMAGE UCS2-Science-Order01.jpg

sometimes X loses to Y’s win. The net neutral co-Action centered to the far left and
above the Y axis represents Y’s win at the total expense of X. The net neutral co-Action
centered to the far right and below the X axis represents X’s win at the total expense
of Y. The net neutral co-Action centered at the ORIGIN (0, 0) represents X and Y both
drawing neither winning or losing. The four other net neutral co-Actions fall
somewhere in between.

Adversary Co-Actions

If the co-Action vector is negative, shorter than the radius of the scalar zero circle it is
a net adversary co-Action. Haskell used the convention of drawing the co-Action
vector from the position inside the zero-zero circle representing X and Y’s condition
from the direction of the(-,-)quadrant to the (0,0) ORIGIN.

A net adversary co-Action vectoris shown below in red ink.

Y

IMAGE UCS2-Science-Order108.jpg

X

(+,+)

(-,+)(0, +)syntropy

(-,-)

(+,-)

(0, -)

(-,0)

(+,0)

(0,0)

Axis of Atropy

entropy

IMAGE UCS2-Science-Order109.jpg

In drawing net adversary co-Actions, the vector is directed towards the (0, 0) ORIGIN
and terminates there. However, it is the position of the back or but end of the vector,
where the guide feathers on an arrow would be found that accurately depicts X and
Y’s condition. Below I have plotted seven net adversary co-Actions.

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